Unformatted text preview: AL AND SHEAR STRESSES shear stress maxima at Θ= 45° max
⌧✓
= normal stress maxima at Θ=0° max
✓ = x x
NORMAL STRESS 2 ✓ = x 2 (1 + cos 2✓) (229a) SHEAR STRESS ⌧✓ = x 2 (sin 2✓) (229b) shear stress “maxima” at Θ=45° 1/17/13 M. Mello/Georgia Tech Aerospace 7 MAXIMUM STRESSES FOR A BAR IN TENSION ²་ Luders’ Bands begin to appear as yield stress is reached ²་ Bands reveal that the material is failing in shear along planes where shear stress is maximum. 45° ELEMENT UNDER MAXIMUM SHEAR STRESS SLIP BANDS (LUDERS’ BANDS) FOR A POLISHED STEEL SAMPLE LOADED IN TENSION (W. LUDERS, 1860) 1/17/13 M. Mello/Georgia Tech Aerospace 8 MAXIMUM STRESSES FOR A BAR IN COMPRESSION 45° ELEMENT UNDER MAXIMUM SHEAR STRESS SHEAR FAILURE ALONG A 45° PLANE IN A BLOCK OF WOOD LOADED IN COMPRESSION 1/17/13 M. Mello/Georgia Tech Aerospace 9 EXAMPLE 2 9: FAILURE LOAD ANALYSIS OF A COMPRESSION BAR GIVEN: ²་ Compression bar made out of structural plas\c must support P=35kN load ²་ Bar constructed of two pieces glued by a joint (scarf joint) inclined by 40°with respect to the ver\cal axis ²་ Allowable stresses in plas\c bar : • max compression: 7.5MPa • shear: 4.0MPa ²་ Allowable stresses in scarf joint : • max compression: 5.2MPa • shear: 3.4MPa GLUED JOINT (SCARF JOINT) DETERMINE: Minimum width (b) of the bar SOLUTION: ²་ Each allowable stress criteria has a corresponding σx ²་ Find σx for each allowable stress criteria and iden\fy the minimum x = P/A bmin =
1/17/13 p Amin Aminimum = P/ b allowable
x bmin
M. Mello/Georgia Tech Aerospace Note: Θ < 0 by sign conven\on 10 EXAMPLE 2 9 (cont.) RECALL GENERAL STRESS FORMULAS: NORMAL STRESS SOLUTION: ²་ COMPUTE σx for each allowable stress criteria for GLUED JOINT x = = 5.2M P a = x = ✓ = ⌧✓ =
⌧✓ = SHEAR STRESS ²་ Max allowable compressive stress: max
glue ✓ x
x 2 cos2 ✓ (1 + cos 2✓) (229a) sin ✓ cos ✓
x
(229b)
2 (sin 2✓ )
x cos2 ( 50 ) 12.6M P a ²་ Max allowable shear stress or GLUED JOINT: max
⌧glue = 3.4M P a = x sin( 50 ) cos( 50 ) NOTE: τ < 0 x = 6.9M P a
NOTE: τ < 0 since shear will tend to rotate either element clockwise 1/17/13 M. Mello/Georgia Tech Aerospace 11 EXAMPLE 2 9 (cont.) SOLUTION: ²་ Max allowable compressive stress: ma...
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 Spring '09
 ZHU
 Force, Stress, Max, max 00

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