{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW13-solutions rusin

# HW13-solutions rusin - rogers(grr459 HW13 rusin(55220 This...

This preview shows pages 1–3. Sign up to view the full content.

rogers (grr459) – HW13 – rusin – (55220) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. Here is a short problem set to get you think- ing about Chapter 15. It’s due ±riday night. There will be one more homework, due next ±riday night (12/7) and then you’re done! 001 10.0 points Evaluate the double integral I = i i A 4 dxdy with A = b ( x, y ) : 2 x 8 , 5 y 7 B by frst identiFying it as the volume oF a solid. 1. I = 52 2. I = 54 3. I = 46 4. I = 48 correct 5. I = 50 Explanation: The value oF I is the volume oF the solid below the graph oF z = f ( x, y ) = 4 and above the region A = b ( x, y ) : 2 x 8 , 5 y 7 B . Since A is a rectangle, this solid is a box with base A and height 4. Its volume, thereFore, is given by length × width × height = (8 - 2) × (7 - 5) × 4 . Consequently, I = 48 . keywords: volume, double integral, rectangu- lar region, rectangular solid 002 10.0 points The graph oF the Function z = f ( x, y ) = 6 - x is the plane shown in z 6 x y Determine the value oF the double integral I = i i A f ( x, y ) dxdy over the region A = b ( x, y ) : 0 x 6 , 0 y 4 B in the xy -plane by frst identiFying it as the volume oF a solid below the graph oF f . 1. I = 73 cu. units 2. I = 72 cu. units correct 3. I = 70 cu. units 4. I = 71 cu. units 5. I = 69 cu. units Explanation: The double integral I = i i A f ( x, y ) dxdy

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
rogers (grr459) – HW13 – rusin – (55220) 2 is the volume of the solid below the graph of f having the rectangle A = b ( x, y ) : 0 x 6 , 0 y 4 B for its base. Thus the solid is the wedge z 6 6 x y (6 , 4) and so its volume is the area of triangular face multiplied by the thickness of the wedge.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern