1873_solutions

# Have h x ae 2x b for every x in other words f x ae x

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Unformatted text preview: n N which we can write as n xn  n xN N . Since xN  1 N we deduce that no partial limit of the sequence n x n can be more than  and, therefore, that the number u cannot be a partial limit of the sequence n x n . lim n Ýn 11 The Riemann Integral Some Exercises on Step Functions 1. True or false? If f is a step function on an interval a, b and c, d is a subinterval of a, b then f is a step function on c, d . Solution: The statement is true. c d b a Choose a partition P of a, b within which the function f steps and then refine P by adding to it the two numbers c and d. Then drop all of the points of this partition that lie outside of the interval c, d and we obtain a partition Q of c, d within which f steps. 2. True or false? If f is a step function then given any interval a, b , the function f is a step function on a, b . Hint: This statement is true. Write a short proof. Choose an interval c, d such that f is a step function on c, d and such that f x  0 whenever x R c, d . Choose numbers p and q such that p is less than both of the numbers a and c and q is greater than both of the numbers b and d p a c b d q Choose a partition P of the interval c, d such that f steps within P. If we add the two numbers p and q to the partition P then we obtain a partition of the larger interval p, q within which f steps. Since f is a step function on the interval p, q , it follows from Exercise 1 that f is a step function on a, b . 3. Give an example of a step function on the interval 0, 2 that does not step within any regular partition of 0, 2 . Solution: We define fx  0 if 0 1 if 262 x 2 2 x 2 Now if P is any regular partition of the interval 0, 2 then, since the irrationality of 2 makes it impossible to find integers n and j such that 2j 2  0 n we know that 2 can’t be a point of P. In other words, the number 2 must be in one of the open intervals of P and f fails to be constant in that interval. 4. Explain why a step function must always be bounded. Suppose that f is a step function on an interval a, b . Choose a partition P of a, b such that f steps with P. We express P in the form x 0 , x 1 , , x n . Since f is constant in each subinterval x j 1 , x j , the range of f must be a finite set and therefore f is bounded. 5. Prove that if f and g are step functions on an interval a, b then so are their sum f  g and their product fg. Hint: You can find a proof of this assertion in the section on linearity of integration of step functions. 6. Prove that if f and g are step functions then so are their sum f  g and their product fg. Choose an interval a, b such that both of the functions f and g take the value 0 at every number in R a, b . We deduce from Exercise 2 that both f and g are step functions on the interval a, b and it follows from Exercise 5 that f  g and fg are step functions on a, b and we conclude that these functions are step functions. 7. Prove that a continuous step function on an interval must be constant on that interval. Suppose tha...
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## This note was uploaded on 11/26/2012 for the course MATH 2313 taught by Professor Staff during the Fall '08 term at Texas El Paso.

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