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**Unformatted text preview: **. gh = Thus m 255 . ) s m 80 . 9 ( ) m kg 1000 ( m N 2500 2 3 2 = = h To keep the bottom gauge pressure at 2500 Pa after the 1500 Pa increase at the surface, the pressure due to the waters weight must be reduced to 1000 Pa: m 102 . ) s m 80 . 9 )( m kg 1000 ( m N 1000 2 3 2 = = h Thus the water must be lowered by m 0.153 m 102 . m 255 . =-...

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