Chapter 11 problems

# Chapter 11 problems - 211/211 Solutions to Problems from...

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211/211 Solutions to Problems from Chapter 11 1. Consider the combustion of cyclohexane. C 6 H 12 ( ) + 9 O 2 (g) 6 CO 2 (g) + 6 H 2 O( ) If the cyclohexane is burning at a rate of 0.350 mol/L•s, at what rates are CO 2 produced and O 2 used up? 12/12 We can express the rate of burning of cyclohexane as: +6 6 12 6 12 6 12 [C H ] 0.350 mol C H rate or combustion of C H = = t L s -∆ g We multiply this rate by the ratio of moles CO 2 to moles C 6 H 12 in the balanced equation: rate of production of CO 2 = 6 12 2 2 6 12 0.350 mol C H 6 mol CO 2.10 mol CO = L s 1 mol C H L s . g g Similarly for the rate of O 2 disappearance: +6 rate of disappearance of O 2 = 6 12 2 2 6 12 0.350 mol C H 9 mol O 3.15 mol O = L s 1 mol C H L s . g g 11 – 1

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2. When a base is added to an aqueous solution of chlorine dioxide gas, the following reaction occurs 2 ClO 2 (aq) + 2 OH (aq) ClO 3 (aq) + ClO 2 (aq) + H 2 O The reaction rate can be followed by monitoring the hydroxide concentration. The following data are obtained: Initial Rate [ClO 2 ] [OH ] (mol/L•s) 0.010 0.030 6.00 × 10 –4 0.010 0.075 1.50 × 10 –3 0.055 0.030 1.82 × 10 –2 0.055 0.062 3.75 × 10 –2 (a) What is the order of the reaction with respect to chlorine dioxide, hydroxide ion, and overall? 40/40 To find the order with respect to ClO 2 , we first choose two experiments where the [OH ] is constant, experiments 1 and 3. The calculation is easier if we put the larger numbers over the smaller numbers. +10 rate rate ClO OH ClO OH ClO ClO OH OH m n m n 3 1 2 3 3 2 1 1 2 3 2 1 3 1 = k [ ] [ ] k [ ] [ ] = [ ] [ ] [ ] [ ] m n × × × × F H G I K J × F H G I K J - - - - 1 10 6 00 10 055 010 030 030 010 5 5 2 4 .82 × × F H I K × F H I K F H I K - - . = 0. 0. 0. 0. = 0.055 0. = ( . ) m n m m 30.3 = (5.5) m 5.5 2 = 30.2 m = 2, the equation is second order with respect to ClO 2 11 – 2
To find the order with respect to OH , we first choose two experiments where the [ClO

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Chapter 11 problems - 211/211 Solutions to Problems from...

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