Unformatted text preview: husband outlived the wife. 7.12 An individual could determine his or her probability of winning this game by playing it a large number of times and recording how many games he or she won out of the total number of games played. 7.17 a. BY, BS, BA, YS, YA, SA. b. 1/6. 7.26 a. The approximate probability = 22/190 = .1158 that a randomly selected person will pick the number 3. b. The approximate probability = (2+6)/190 = 8/190 = .0421 that a randomly selected person will pick either 1 or 10. c. The approximate probability = (2+22+18+56+14)/190 = 112/190 = .5895 that a randomly selected person will pick an odd number. 7.35 a. No, they are not independent. P(A in both classes) ≠ P(A English) × P(A in history), as it would for independent events. b. P(A in either English or history) = P(A in English) + P(A in history) P(A in both classes) = .70 + .60 .50 = .80....
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 Spring '08
 BARROSO,JOAOR
 Statistics, Probability, probability applies, relative frequency interpretation

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