problem14_28

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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14.28: The rock displaces a volume of water whose weight is N. 10.8 N 28.4 - N 2 . 39 = The mass of this much water is thus kg 102 . 1 s m 9.80 N 8 . 10 2 = and its volume, equal to the rock’s volume, is 3 3 3 3 m 10 102 . 1 m kg 10 1.00 kg 102 . 1 - × = × The weight of unknown liquid displaced is
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Unformatted text preview: N, 20.6 N 18.6 N 2 . 39 =-and its mass is kg. 102 . 2 s m 9.80 N 6 . 20 2 = The liquid’s density is thus 3 3 m 10 1.102 kg 102 . 2-× , m kg 10 91 . 1 3 3 × = or roughly twice the density of water....
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