SCM 300 - Lab 4.docx - SCM 300 u2013 ONLINE LAB EXERCISE#4...

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SCM 300 – ONLINE LAB EXERCISE #4 STUDENT VERSION YOU MUST SHOW YOUR WORK TO RECEIVE CREDIT ONLINE Lab Exercise #4 (25 Points) SCM 300 PART 1: Queuing The local coffee shop has 2 employees, one takes the orders and then takes payment, and the other worker makes the coffee drinks. While some folks ask for a simple cup of coffee that just needs to be poured, others ask for more elaborate coffee drinks, and others order multiple drinks. On average, though, it takes a total of 1 min and 15 seconds to process a customer, take the order, make the payment, and make the drink(s). During the busiest time of the day, 7:30am to 9:30am, about 39.5 customers come in per hour: 1. (2 POINTS) Since the two workers only service one customer at a time, they are in fact working like a single worker. What percentage of the time is this single team of workers busy? 60/75 = .8*60 = 48 P = 39.5/48 = .823 2. (2 POINTS) What is the average time a customer waits before they place an order? (In minutes) Time in line = .823 (1/(48-39.5)) = .0968*60 = 5.81 3. (2 POINTS) What is the average number of customers in the line? Number in line = .823(39.5/(48-39.5)) = 3.82 4. (3 POINTS) Your company used to employ 1 computer technician, Olivia, at a cost of $20/hour who could fix 2.9 computer problems per hour. Olivia retired.

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