problem14_40

University Physics with Modern Physics with Mastering Physics (11th Edition)

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14.40: From Eq. (14.17), with , 2 1 y y = ( 29 2 1 1 2 1 2 1 1 2 2 2 1 1 2 8 3 4 2 1 2 1 ρv p v v ρ p v v ρ p p + = - + = - + = ( 29 ( 29 Pa, 10 03 . 2 s m 50 . 2 m kg 10 00 . 1 8 3 Pa 10 80 . 1 4 2 3 3 4 × =
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  • continutity relation

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