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**Unformatted text preview: **14.46: a) See problem 14.45; the net force is dF from h = 0 to h = H , F = gH 2 2 = gAH 2, where A = H . b) The torque on a strip of vertical thickness dh about the bottom is d = dF ( H - h ) = gwh( H - h ) dh, and integrating from h = 0 to h = H gives = gwH 3 6 = gAH 2 6. c) The force depends on the width and the square of the depth, and the torque about the bottom depends on the width and the cube of the depth; the surface area of the lake does not affect either result (for a given width). ...

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