problem14_51

University Physics with Modern Physics with Mastering Physics (11th Edition)

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Unformatted text preview: 3 3 2 -2 3 14.51: a) water ghwater = (1.00 10 kg m )(9.80 m s )(15.0 10 m) = 1.47 10 Pa. b) The gauge pressure at a depth of 15.0 cm - h below the top of the mercury column must be that found in part (a); Hg g (15.0 cm - h) = water g (15.0 cm), which is solved for h = 13.9 cm. ...
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