problem14_58

University Physics with Modern Physics with Mastering Physics (11th Edition)

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Unformatted text preview: , where fluid is the average density of the hydrometer (see Problem 14.23 or Problem 14.55), which 1 . Thus, if two fluids are observed to have floating can be expressed as fluid = 1- f 1 - f1 . In this form, it's clear that a larger f 2 corresponds to fraction f1 and f 2 , 2 = 1 1 - f2 a larger density; more of the stem is above the fluid. Using 2 2 f1 = (8.00 (cm)(0.400) cm ) = 0.242, f 2 = ( 3.20 (cm)(0.400) cm ) = 0.097 gives 3 3 13.2 cm 13.2 cm 14.58: alcohol = (0.839) water = 839 kg m3 . The fraction f of the volume that floats above the fluid is f = 1 - ...
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This document was uploaded on 02/05/2008.

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