problem14_61

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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14.61: a) ( 29 ( 29 ( 29 m. 107 . 0 m 450 . 0 m kg 10 03 . 1 kg 0 . 70 2 3 3 = × = = = = π ρA m ρgA mg ρgA w x b) Note that in part (c) of Problem M , 60 . 14 is the mass of the buoy, not the mass of the man, and A is the cross-section area of the buoy, not the amplitude. The period is then
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• Mass, kg, gA gA

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