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Unformatted text preview: Fundamentals of Physics Halliday & Resnic 東東東東東東東 98 東東東東 2 東東 系系系□0401 系系系 □0409 系系系系系 系系系 系系系 . 系CH30系Inductance 1, 5, 7, 11, 13, 15, 21, 29, 31, 34, 37, 39, 45, 47, 51, 57, 63, 65, 73, 75 系Problem 301系 In Fig. 3037, the magnetic flux through the loop increases according to the relation 2 6 7 B t t Φ = + , where B Φ is in milliwebers and t is in seconds. (a) What is the magnitude of the emf induced in the loop when 2 t s = ? (b) Is the direction of the current through R to the right or left? 系系 3037系 <系>系(a) The magnitude of the emf is ε = = + = + = + = d dt d dt t t t B Φ 6 0 7 0 12 7 0 12 2 0 7 0 31 2 . . . . . c h bg mV. (b) Appealing to Lenz’s law (especially Fig. 305(a)) we see that the current flow in the loop is clockwise. Thus, the current is to left through R . 系Problem 305系 In Fig. 3039, a 120turn coil of radius 1.8 cm and resistance 5.3 Ω is coaxial with a solenoid of 220 turns/cm and diameter 3.2 cm. The solenoid current drops from 1.5 A to zero in time interval 25 t ms ∆ = . What current is induced in the coil during t ∆ ? 系系 3039系 <系>系The total induced emf is given by 東 1 東東東 13 東 Fundamentals of Physics Halliday & Resnic 東東東東東東東 98 東東東東 2 東東 ( 29 2 2 ( ) ( ) 1.5 A (120)(4 T m A)(22000/m) 0.016m 0.025 s 0.16V. B d dB d di di N NA NA ni N nA N n r dt dt dt dt dt ε μ μ μ π Φ =  =  =  =  =  ÷ =  × × ÷ =7 π 10 π Ohm’s law then yields  / 0.016 V /5.3 0.030 A i R ε = = Ω = . 系Problem 307系 In Fig. 3040, a wire forms a closed circular loop, with radius 2 R m = and resistance 4 Ω . The circle is centered on a long straight wire; at time t = , the current in the long straight wire is 5.0 A rightward. Thereafter, the current changes according to 2 2 5 (2 / ) i A A s t = . (The straight wire is insulated; so there is no electrical contact between it and the wire of the loop.) What is the magnitude of the current induced in the loop at times t ? 系系 3040系 <系>系The field (due to the current in the straight wire) is outofthepage in the upper half of the circle and is into the page in the lower half of the circle, producing zero net flux, at any time. There is no induced current in the circle. 系Problem 3011系 A square wire loop with 2.00 m sides is perpendicular to a uniform magnetic field, with half the area of the loop in the field as shown in Fig. 3044.The loop contains an ideal battery with emf 20 V ε = . If the magnitude of the field varies with time according to 0.042 0.87 B t = , with B in teslas and t in seconds, what are (a) the net emf in the circuit and (b) the direction of the (net) current around the loop?...
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This note was uploaded on 10/08/2013 for the course PHY 301 taught by Professor Swinney during the Fall '07 term at University of Texas.
 Fall '07
 Swinney
 Physics, Inductance

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