problem14_64

University Physics with Modern Physics with Mastering Physics (11th Edition)

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14.64: The buoyant force on the mass A , divided by kg 70 . 4 kg 80 . 1 kg 1.00 kg 7.50 be must , = - - g (see Example 14.6), so the mass block is kg. 8.20 kg 3.50 kg 70 . 4 = + a) The mass of the liquid displaced by the block is kg, 70 . 4 so the density of the liquid is
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Unformatted text preview: . m kg 10 24 . 1 3 3 m 10 3.80 kg 70 . 4 3 3- = b) Scale D will read the mass of the block, kg, 20 . 8 as found above. Scale E will read the sum of the masses of the beaker and liquid, kg. 80 . 2...
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