problem14_65

University Physics with Modern Physics with Mastering Physics (11th Edition)

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14.65: Neglecting the buoyancy of the air, the weight in air is N. 0 . 45 ) ( A1 A1 Au Au = + V ρ V ρ g and the buoyant force when suspended in water is N. 6.0 N 39.0 N 45.0 ) ( A1 Au water = - = + g V V ρ These are two equations in the two unknowns . and A1 Au V V Multiplying the second by A1 ρ and the first by water ρ and subtracting to eliminate the A1 V term gives N) 0 . 6 ( N) 0 . 45 ( ) ( A1 water A1 Au Au water ρ ρ ρ ρ g V ρ - = -
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Unformatted text preview: N) . 45 ( ( ) ( Au water A1 Au water Au Au Au Au ρ ρ ρ ρ ρ ρ gV ρ w--= = N)) . 6 )( 7 . 2 ( N) . 45 )( 00 . 1 (( ) 7 . 2 3 . 19 )( 00 . 1 ( ) 3 . 19 (--= N. 5 . 33 = Note that in the numerical determination of , Au w specific gravities were used instead of densities....
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  • Buoyancy, Au wAu, unknowns VAu, Au gVAu

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