problem14_70

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
14.70: a) Let d be the depth of the oil layer, h the depth that the cube is submerged in the water, and L be the length of a side of the cube. Then, setting the buoyant force equal to the weight, canceling the common factors of g and the cross-section area and supressing units, - = = + + = + L h L L h d L h d L d h (0.65) so , (0.35) by related are and , . ) 550 ( ) 750 ( ) 1000 ( d . Substitution into the first relation gives m. 040 . 0 5.00 2 (750) (1000) (550) 0) (0.65)(100 = = = - - L L d b) The
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: gauge pressure at the lower face must be sufficient to support the block (the oil exerts only sideways forces directly on the block), and Pa. 539 m) 100 . )( s m 80 . 9 )( m kg (550 2 3 wood = = ρ = gL p As a check, the gauge pressure, found from the depths and densities of the fluids, is Pa. 539 ) s m 80 . 9 ))( m kg m)(1000 025 . ( ) m kg m)(750 040 . (( 2 3 3 = +...
View Full Document

This document was uploaded on 02/05/2008.

Ask a homework question - tutors are online