Chapter 3

# T gt 2 2 2 problem solving free fall an 5 kg ball

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Unformatted text preview: city (v) after a time interval (t) is: velocity for free fall g= 10 m/s/s t=times v = gt •  The distance (d) an object falls in a time interval (t) is given by: 1 1 d = g(t ! t ) = gt 2 2 2 Problem Solving: Free Fall •  An 5 kg ball falls off of the top of Memorial Tower. –  What is its velocity after 1 s?, 3 s? –  How far has it traveled after 1 s?, 3 s? •  Velocity: –  1 s: v = (9.8 m/s/s)(1 s) = 9.8 m/s –  3 s: v = (9.8 m/s/s)(3 s) = 29.4 m/s A free-falling object has a speed of 30 m/s at one instant. exactly 1 s later its will be" A. the same B. 35 m/s C. more than 35 m/s answer- c it is be 40 m/s •  Distance: 1 –  1 s: d = (9.8 m/s/s)(1 s)(1 s) = 4.9 m 2 –  3 s: d = 1 (9.8 m/s/s)(3 s)(3 s) = 44.1 m 2 Summary: 5...
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## This note was uploaded on 10/15/2013 for the course PHSC 1001 taught by Professor Gregg during the Fall '06 term at LSU.

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