Unformatted text preview: tery and diode polarities, assume the diode is forwardbiased. Replace the diode
with a piecewise linear model as shown. Then
(
( ( This voltage is consistent with the assumption that the diode is forward biased. 16 55:041 Electronic Circuits. The University of Iowa. Fall 2011. Problem 14 For the following circuit, determine
resistance is negligible and that
. . Assume the diodes’ internal and Solution
Assume that both diodes are forwardbiased. Replace the diodes with linear models as shown
below. This is now a linear circuit that one can solve using nodal analysis, KCL, KVL,
superposition, Thevenin or Norton equivalent circuits, etc. A KCL equation for the output node is
(
Solving yields
are forward biased. ( The sign of the voltage is consistent with our assumption: the diodes The current through the output resistor is
flows through each diode, so that ⁄ = 3.1 mA. By symmetry, half of this current 17 55:041 Electronic Circuits. The University of Iowa. Fall 2011. Problem 15 For the following circuit, determine and Assume for Si is 0.7 V and for Ge is 0.3 V, and the diodes’ internal resistance is negligible.
Solution
Given the battery and diodes’ polarities, assume the diodes are forwardbiased. Replace the
diodes with piecewise linear models as shown. Then by inspection, and This voltage is consistent with the assumption that the diodes are forward biased. 18 55:041 Electronic Circuits. The University of Iowa. Fall 2011. Problem 16
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This note was uploaded on 10/26/2013 for the course ECE 55:041 taught by Professor Kruger during the Fall '11 term at University of Iowa.
 Fall '11
 Kruger

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