This preview shows page 1. Sign up to view the full content.
Unformatted text preview: of Iowa. Fall 2011. Problem 11 For the following circuit, determine
and . Assume the diodes’ internal
resistance is negligible, and that
for Si is 0.7 V and for Ge it is 0.3 V. (6 points) Solution
Given the polarity of the battery and diodes, assume that both diodes are forward biased.
Replace the diodes with piecewise linear models as shown below. This is now a linear circuit
that one can solve using nodal analysis, KCL, KVL, superposition, Thevenin, or Norton
equivalent circuits, etc. A KCL equation for the Si diode node is Solving yields
. The sign of the current is consistent with the assumption that the
Si diode is forward biased. By inspection 14 55:041 Electronic Circuits. The University of Iowa. Fall 2011. Problem 12 For the following circuit, determine . Assume for Si is 0.7 V and for Ge is
0.3 V, and the diodes’ internal resistance is negligible. (4 points) Solution
Given the battery and diodes’ polarities, assume the diodes are forwardbiased. Replace the
diodes with their piecewise linear models as shown. Then ( ( Alternatively, note that the 4.75 mA flows through the output resistor, so This voltage is consistent with the assumption that the diodes are forward biased. 15 55:041 Electronic Circuits. The University of Iowa. Fall 2011. Problem 13 For the following circuit, determine
internal resistance is negligible. . Assume for Si is 0.7 V, and the diode’s Solution
Given the bat...
View
Full
Document
This note was uploaded on 10/26/2013 for the course ECE 55:041 taught by Professor Kruger during the Fall '11 term at University of Iowa.
 Fall '11
 Kruger

Click to edit the document details