exam3spr07form1expl-1 - Third exam, FORM 1 page 1...

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Third exam, FORM 1 page BIO201C/Hon—Janicke—Spring 2007 If you have not already done so, IMMEDIATELY fill in the bubbles on the back of the answer sheet for (1) your name (LAST NAME FIRST) (2) 8-digit person number, (3) seat number (4) FORM 1 (under “GRADE or EDUCATION”) On the front of your scantron on the top line, sign your name and the code word “half-way.” Do it now, because when the exam is over, you must stop work when told and will be given no extra time to do ANYTHING. You will be assigned a score of ZERO if you hand in a scantron with no name on it, fail to fill in your form number, use notes of any kind, or copy another student’s work. Other procedural errors in your scantron or in exam rules (such as hats, calculators of your own, cell phones heard or seen, or talking) will result in deduction of 5 points (if cheating is NOT suspected). Be sure erasures are complete. You may ask for a new scantron if you’ve ruined yours. CHOOSE ONE AND ONLY ONE ANSWER PER QUESTION. 1. We know from lab 4 that in the dark, DCIP (becomes , does not become ) reduced by water and (becomes, does not become ) reduced by chloroplasts. The redox potential of DCIP is (higher, lower ) than that of water and (higher, lower ) than that of unexcited reaction center chlorophyll. A. becomes, becomes, higher, higher B. does not become, does not become, lower, lower C. becomes, does not become, higher, lower D. does not become, becomes, lower, lower E. does not become, becomes, higher, lower 2.In the presence of light, P680* becomes a strong enough (reducing , oxidizing) agent to donate electrons to a primary electron acceptor in photosystem II. Those electrons can be intercepted by DCIP before they get to photosystem I. The loss of electrons from P680 leaves an “electron hole” in P680- which is filled by (reduction, oxidation) of water. DCMU binds to a site that plastiquinone usually binds on photosystem II. With DCMU bound there, electrons (can, cannot ) be passed to photosystem I or to DCIP, and ( increased , decreased) fluorescence occurs. A. reducing, reduction, can, decreased B. reducing, oxidation, cannot, increased C. oxidizing, reduction, can, decreased 1
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Third exam, FORM 1 page D. oxidizing, oxidation, cannot, decreased E. oxidizing, reduction, can, increased 3. What is the velocity of a 100S particle spun at F=1,000 g (which is about 10^6cm/sec2)? 1S= 10^-13 sec. V=SxF. A. 10^-11 sec x 10^6 cm/sec2 = 10^-5 cm/sec. B. 10^-15 sec x 10^6 cm/sec2 = 10^-9 cm/sec C. 100 sec x 10^6 cm/sec2 = 10^8 cm/sec D. 10^ -3 sec x 10^-13 cm/sec2= 10^-16 cm/sec E. 10^-13 sec x 10^ 3 cm/sec2 = 10^-10 cm/sec 4.What channels are responsible for the portions of the action potential indicated above? 1
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This test prep was uploaded on 04/08/2008 for the course BIO 201 taught by Professor Janicke during the Spring '08 term at SUNY Buffalo.

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exam3spr07form1expl-1 - Third exam, FORM 1 page 1...

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