Exam2 CE250 - ‘%QE ENGINEERING SURVEYING “’3; V...

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Unformatted text preview: ‘%QE ENGINEERING SURVEYING “’3; V Examination 2 V FaH2007 Name PROBLEM 1a. A horizontal circular curve for a road centerline has a point of intersection at station 35 + 20.00, has a degree of curvature of 8 degrees (radius of 716.20 feet), and a total deflection angle of 60 degrees. Sketch the curve. What is the deflection angle (when set up at the point of curvature) that must be turned to stake the first full engineering station (at 100 ft intervals) on the curve? (6 points) : “)1w.1+0fl( T: K Jf-L/‘lzi‘ji €c= 3570’— 7135' (Vééo TD Ware 3 z+oo :«M/(A I“; 4tb0 a 73'5’ Aéoye cum/$3” I \ . 5163» 5‘ I 9 :— 5. - \\\\ \ '1 :L O! (3 < l \ ‘\\ f, / / y\&< A: ‘~Mé< \ y/ #WIW “(fat/9‘ , ’ \ I; / v / r ~33, PROBLEM 1b. For the chve in Part a, what is the straight-line distance between the point of curvature and the first full engineering station on the on the curve? (3 points) ' ,,”<-‘{\"\ l 31/ M W. W k -> ’ n ’I/‘W'LJ? ’2' («(Q 510$; .2-) ' ’13! 7 .1 . I ' I) 2'5"” 1“; d ‘ - 3 . :,~\ ,Ng‘a‘ .- I , Lwa ms? 5"“ 3 I +‘ 00 -‘->’ a PROBLEM 2. The elevations of grid points of a small, square lot are shown below. Sketch the location of all 1 ft contours through the lot. Leave sufficient information on the drawing to indicate your method of solution. (5 points) V./’”@ .77 PROBLEM 3. The coordinates of the corners of a 4-course traverse are shown in the drawing below. The units for the coordinates are feet. Compute the area of the traverse by use of the coordinate method. (5 points) )9 (x=110.00, y=85.00) 9' '4 y’f . (x=.50.00, y=65.00) / ‘ L " // (x=150.00, y=60.00) “7 3 3 02:60.00, y310.00) 50(10— 83) + 00((pO-tgf)riso(85'1i$'f'5"’{.@3“w} : «Q32 twee “K PROBLEM 4. While using a transit with stadia (constant = 100), a surveying crew A observed that the apparent vertical distance between the upper hair and the lower hair was 3.10 feet on a Philadelphia rod. The vertical angle was exactly +8 degrees. What is the horizontal distance between the instrument and the rod? (5 points) I 1 DL hr (gr) L 1% (€21th ; 3,:093 (no) C05(8> C0363) 7' )30‘7/ p ’j‘x ( WMM’M’flW PROBLEM 5. Answer 3 short questions. (2 points each) a. What are NAD 27 and NAD 83 why do we need to know the differences between them? '.\ 774% é :4" its. 'f;;a,.:::2 EL: 9535 i STPFFe Pit/We gmeerfliNfl'Te 5.75 79”} b. Columbus, Ohio has a longitude of —83 degrees and a latitude of 40 degrees. Approximately what bearing would someone from Columbus need to travel to their vacation spot which is at a longitude of -84 degrees and a latitude of41 degrees? Briefly explain your reasoning. ’ “The n1 93"” w c. When is it appropriate in surveying to use double centering? What purpose does it serve? , (/JhL/l am amle Cur :3: :‘4/fl/l’ K‘L‘m‘iflivf/v ——‘"“v“" P PROBLEM 6. Consider the four-course loop traverse shown below. The bearing of Course AB is N 0° 0’ E. Point A has coordinates of x=1000.00, y=1000.00. The adjusted interior angles of the traverse and the measured lengths of each course are shown below. Adjust the traverse with the compass rule and report the coordinates of station C. Hint: there is no error in the departure. (10 points) B Q! v “90803 1 3190“ C (r) 5 a1» : O lr\\ \\ — qu‘ _ be? (:54, :. L/ao 5m (‘50; * 3‘90 /\ L01" EL = 7'30 CdfiCfi‘J} 2 -—'Z_S7, It {v / A De? Co = O .V (lamina...) La+ c0 :— -® 00’5—0 D (be? DA : €100 sinlSv‘) "—3%IV1 misfit” or ox} 1» we sic-Jaws“; 7"“ ‘" A lnterioroAngle B 1300 0’ Ag: 0 a fog? : 0 50 O 2, c. = $63-90 7" ‘fio C 130°0’ EL”: WIS D 500 0: CD ; 1301490 —1§o= [2,0 m 99 1 310 i ;-- 5- 2 _ 3-41. ' 0/ _ ngyr MISLIUW'C. "' 0 + (9' ) A930 Wimp/1L 7 ’— ZOOO'S 045 (900) _ 0416 1— 600 :2 (DOOM; AG) 2000,?» K I ‘ 93¢ 221,112":— », O“ + -7,§7,47. = ~Zs7.o1 A- (1000‘ IDs-u) Tagfl‘I: . g Lloao) Woaqs’) CD '; a” 0.13" —(aug.5" '» -(poo«35’ _ -' ,g’glfimg IC<’3°""’ZI “Lads; J De —. Wage-'2") ,, OJ + 157,1: -— 2-37.11 7a.,» .43 _, 1‘ EXTRA CREDIT \A. Refer to Problem tab. What cord and deflection angle is needed to stake the point of tangency? (3 points) m ,1: ; l 30 a l «‘1’ \ 1 {/m-i/ 9—9 a "MA T ‘. “ M. ‘\ ’37” z zli 5x017. "-‘ 1Q 7’“’1Ol5’”(‘1) ' (Li/(9‘ Zwfilwr’”) «‘3 ‘ (/II l . ‘3 mu“ “m Xxx 7 “Jae-4‘35“ F . “a _ -.—. A" V /, B. Refer to problem 5b. The person from Columbus is the trip to his vacation spot by helicopter. What distance does the helicopter ne 0 fly? (3 points) C. A sun/eyor is trying to place a stake on a direct line between points A and B by wiggling—in. B is due east of A and are about 600 feet apart. He sets up his instrument at . point C which is 200 feet from A and 400 feet from B. He then extends the line AC towards B and drops a stake 1.20 feet north of B. To where should he move the instrument next (from C) to be on the best alignment with A and B? (3 points) Ema M eeWLIflAfur Ve©;‘n\3 Exam ‘1 wwows \ , - r 9-5 ’1’ R‘l’w’lik =- 46.50 (,0 Vt: 3420 “H3 .30 = Ben-56.30 11.: Mo (3.00 4006.52; =— (13.50 VG Pr &a 9.3.50'J-‘3/Ioo: 149° H S = 4/2 ‘- 3.—7fz-°~ 3644’24 gr 2(7xé.'z¢)sm 374°: €13,434} v 3375 (3&1 @ L: goo+goc+4oo+40c> =- 2.000 6,, = GOO‘eoOJ’b £0.50 CNN). (goodness/awn: O cwJr BC, -.— 4-be wfi/wee = 64 LA M3 = $00.00* 0.6: “60046; Veg/355: o $00 (05% J 506.47- L-ask BC; : «(+00$|i\40 ‘V 0.10 = - 2.37.02 KL: woo-r Was—257,52 = 6+5‘13Qk \l‘c. = “>06 * 0 + 36(s41a 806.4244 Pess‘rch-z 1;.- 4-D MGR = 43.3 Lou) 1‘ \Q “swam = 2%.?) A ...
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Exam2 CE250 - ‘%QE ENGINEERING SURVEYING “’3; V...

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