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Exam 2 CE490

# Exam 2 CE490 - Transportation Engineering 4 Q Exam 2...

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Unformatted text preview: Transportation Engineering 4 Q Exam 2 Fa112007 Name PROBLEM 1. Observe the simple network below showing free travel times in minutes on ﬁve links. Origin to destination vehicle ﬂows for a single hour are given in the table. Based on the ' free travel times shown for each link on the network. assign the vehicle trips to the network using all-or-nothing trafﬁc assignment and show the volumes On each direction of Peach and Elm Streets. The “practical” capacity of each link is 1800 vehicles per hour. What should be the recalculated travel time on eastbound Elm St. (toward A) given the traditional (1964) BPR travel time formula? (10 points) IIII Ila-II! III PROBLEM 2. The Foxville Apartment Complex is just 1.5 miles from downtown. Each day 200 people make this trip. There is direct bus service between these two locations. Time by bus for a single trip consists of 10 minutes of riding, 6 minutes of waiting and 8 minutes of walking. Bicycle time is 15 minutes'foWDriving time for a single trip is 9 minutes (including walking to and from parking). Drivers travel alone. It costs \$6.00_to park for a day, and the bus fare is \$1.00 for each ride. How many people will take the bus? Use the coefﬁcients presented in problem 4-18 in the textbook and am = 0 for automobile and am = -2.0 for bicycle and am = -0.40 for bus. Assume walking and biking time are “line—haul” times. (10 points) 6115 MM: —04_f/o -o,oNoam/Awe:Kayompafmowgﬁ : 8M Uw= - M7. ' - 7‘1 ~ (6 N"? \ .. .. _ 5‘ 2 o . 0 < U“, ., 0 Cum?) (9,05 (q) rOIOOZ boo)/ of“; :34 ’Ibg” V “(at 1' —l'.3—5g / i . x" O (0 Um: —2-'0 " ”9’51 > :1 :ovmn “/5443 2 — 2,123 ‘/ X: .’ Veoachs 4.11: P —, M " ow 8‘” Q" (”1— el’ * ‘ 7 A ‘_ ?‘ / Woo/0 'owtc Take me so: ; ‘7: Pap/e, \ 7400/] /\ PROBLEM 3. A horizontal curve on a six-lane highway in Wisconsin is being resurfaced. .The road’s design speed is also being increased from 50 to 69 mph. Because of existing urban development the {Wanna be changed from its current value of 1200 feet. Find the superelevation (rounded to the nearest hundredth) that should be used for the new design . speed according to AASHTO standards. NWOI this road will be 0.02. (5 points) 6V '2. [2,00 ’ ‘ . f 7 Z 523m Mm F1 2 - 60“?“ (awe/IIBB'Z 68/5 3 / - g . Vt 33,“ Q con/1w 0.17. / + 1 ___,,_,_. 3/ 9. 51A '~ 3 KV PROBLEM 4. The road of PROBLEM 3 has 12 foot lanes and no median. A large spruce tree is located 50 feet from the centerline within the curve. Should the tree be cut down to assure that safe sight distances can be maintained at the new design speed of 60 mph? (5 points) Kill!” 3‘? (plant . Pam auT szoe— u-nc, I — 250:3'4170 . O 550 ‘ so’—- 2.51m) a 20 (43" \$Vi(i‘C/05 V rev > Tébk- 7,0 M5;Z‘>l p @ (gawk \$30 :- 370 o o) ? <H—l) a? 70 We M cf 5a?— (‘3 :34, Far m 550 Nbéoéo 5. 5 2 771611“: I; w’ 59 7r uauLO N660 TD @eLuT pow F PROBLEM 5. A highway engineer must design a vertical curve to connect a upward 6% grade with an downward 4% grade. The curve is 1200 feet long. The point of intersection is at STA 55+00. 00 and has an elevation of 638. 22 it. This is a multilane rural road with a design speed of 60 mph. Sketch the curve. Find the elevation STA 58+00 on this curve. (8 points)\$+(90 063 5 é ; (4‘2, VP]; -— 67A 55700 79' ales/.1 (£53122 Lalwo' S?®0Mfk /§\/PC_: Ssroo —— ”:0’ 797“” V l eleu ‘- 938 2?. » 01°®(®©O>"’_®OZ.LZ 579 5'8“”? S9 +w , 97m: ' 7&0’ PROBLEM 6. The Rockwell Automation. is plarming an 80-acre manufacturing facility with 1200 employees. Using average trip rates from IT E Trip Generation, what is the best estimate of the number weekday vehicle trips will be made from and to this site? (3 points) T: 38.88 (90 am; r— sued vat/”c Hes/Wu” '/ T: 7;,10 (/1005 ‘— ZS 233551}ka ‘hr‘fs/Wekokﬁ o-< ' gL‘J‘L ”ﬁnal/{C 3} l0 “b PROBLEM 7. An automobile collided with a disabled truck. The crash investigator measured the skid marks as being 180 feet long and estimated the speed of impact at 15 mph. Road conditions were dry and level. The car did not have antilock brakes. Is there reason to suspect that the driver was exceeding the speed limit of 45 mph? State all assumptions and show all calculations. (5 points) , A 4,;( 5:2: 2: QQJS' ﬁé ﬂ 7 . g —, 0/3/ Q7 v5mf’ A Is «(A (pig—:3) 2. 22.0: 95 L Z . '1 —- --L A? W a v0 — v? 95:13”- 22:93.. > ”7,93 Q €‘ “(“63 .. Z<3blll®wu 1 /F 77% 0M our) eowé LIsmfal,‘ :T waaLD N590 laid-33% 7°: ' 51,91) To Ismrk 50 ﬁle (ma was ma‘r 9am, ("ﬁSTeQ THAN Hf lllllrmguuw Extra credit: PROBLEM A. A ﬁeeway between Foxville and Doveﬁeld consists of three lanes. Heavy trucks, being 20% of all vehicles, must use the right-hand lane. Because of the trucks, the travel time ﬁmctions differ between the right-most lane and the two left-most lanes. 2 2 V ' V t- =201+0.80 t =161.+0.8 "g" [ (1800] i ’4‘ i [4000] i where v is the number of passenger car equivalents for all trafﬁc in the 1ane(s). Will any automobile drivers chose to use the right lane, according to Wardrop’s ﬁrst principle, if the total volume (cars plus trucks) is 6000 vehicles per hour? (Calculat'ons must be shown.) (Hint: you don’t need to actually calculate the volume in each lane .yﬁﬁints) PROBLEM B. Refer to PROBLEM 5. Does this curve have sufﬁcient sight distance according P to AASHTO standards? (3 points) -— L (9* ALIGL’GIi "‘ (—‘f‘bl '— log/o ’ MOO. + SW5) 0‘10 {V L 200 A 1’ Sf, A:\ lZaO(z.oo(—L + S +,,,(f)\>: /CD 52 / mmL 7' ZS " A—_._ S : 5/2 ’6‘- @- < L ak / 6 Mill LMIW Tm5/L 7'9 éo/V‘PL“ 530 7- €70 [JO'J/ ell/905,4 PROBLEM C. Should there be law against residents planting spruce trees within 20 feet of a corner at uncontrolled (no signs or signals) intersections in residential areas? Explain your reasoning, list your assumptions, and provide any supporting calculations. (3 points) 0 Yffa if can block. vfsdbnlﬁ ‘FCK “11302;; on \$35.5 sifvcw": / ‘l’ufnirv5 onlD‘fAc" ”‘4’. fé‘d‘ ,/\C’? <5 N. ﬂQWcSPa/‘JLQ (on aatﬂecrm Egom, ’1 Anemia/5 FZJI gag , «Cb Mk skw“ Wes \cc}; “hag Sam: pmgL‘ W): TWMBA z: a \$306 ”00+qu /‘ EVan 2J0!) ngzzkoo 5°““’°° X: \b (H 045 (2466/ \$5034): \23'3 WI», ®Utous ‘~'-' ‘."t -‘ 0.02.9 + ‘8 ~ o.o32\$(, — 0,0549 lO - 0.002.. (Log) .1- .— “4.2. U“, = o - c.0351“? - 0.062(900/131: «>355 lem" ‘2. ~ 0.0\S~u5 .:.- «112,5 27 0.0804: \$\-9k\' p, 6 .- (kW/(6mg ~93»; 6—22.03: 0756:. MCth—IM Ak5m§ Maul T; 100* 0.367. =‘ (:0 ﬂ as @ [Zr—L \zoo~1(n)—‘6>=\\1o‘, 4mg is 20% (m. «swig \AVR. ‘1‘»: l\'1DC\- (_os(ﬁo.y\$7o/7<~vu10) c. 6°n\$47 20 a7 “3"“ <3) awn z (“Hf“)? 32.2w): \20° ® 55+“) “\$27- \$=qoo; mm..- 0.06 (3cm) + (939.1,; .-. eye-.27.; v?c u<\$+ 3an = ‘toﬁa‘rﬁ 04/2!!! ‘LOO 5‘ 33:75" U5.- 634.221-‘w33.76'= aux?) -G-‘r R Q) T: 1.40 4: \100 2320 «J. {Jr/as WW @ NNLT-J m3: @1—zz‘)/z+sz.2+o.c, a 4.- 36.7,szpqsecw 5?.ewf‘15Q)‘\. ssnsu: = +€>3 Hum = ‘té; Low _- L425) mom“ = 36.5 ...
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