Quiz 1 Solutions

Quiz 1 Solutions

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Unformatted text preview: n the plane x + y − z = −1. Indeed, in the above plane equation, if we substitute x = 2t + 1, y = 4t + 2, and z = 6t + 1, then we obtain ( ∗) 2t + 1 + 4t + 2 − 6t + 4 = −1. The left-hand side of this identity is simplified as −1. In other words, the identity (∗) holds for an arbitrary t ∈ R . [V] (4pts) (1) The equation x2 − y 3 = 0 represents a curve having a cusp at the origin, lying in the upper-half plane. The curve is unbounded. The curve has a mirror symmetry along the y -axis. The curve has no as...
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This note was uploaded on 11/06/2013 for the course MATH 223 taught by Professor Staff during the Fall '08 term at Kansas.

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