{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# Problem 3-1 - Example 3-1 A two-phase steam-water mixture...

This preview shows pages 1–3. Sign up to view the full content.

Example 3-1 A two-phase steam-water mixture with a quality of 0.77 and temperature of 140°C expands reversibly and isothermally in a piston-cylinder assembly. The final pressure is 200 kPa. If the initial volume is 20 cm 3 , determine: a) the final volume b) the heat added c) the work done d) Show the process on a P-v diagram Solution: a) First find the mass in the cylinder. The specific volume at state 1 is 3 1 m VOLUME(steam, 140, 0.77) 0.392 kg vT x == = = 3 3 5 1 3 1 1m 20 cm 100 cm 5.1 10 kg m 0.392 kg V m v ⎛⎞ ⎜⎟ ⎝⎠ To get the final volume 3 2 m VOLUME(steam, 140, 200) 0.935 kg P = = () 3 3 5 22 m 100 cm 5.1 10 kg 0.935 kg 1 m Vm v × 3 2 47.7cm V =

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
b) To find the heat transferred, we note that for a reversible process like this one QT d S δ = d S = () ( ) 21 2 1 d ST S S T
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 3

Problem 3-1 - Example 3-1 A two-phase steam-water mixture...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online