Review Quiz3 and final Part 1

# Back the first decfsz instruction will execute for

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Unformatted text preview: decfsz instruction will execute for 256 times. DELAY_L will become 0 after the 256th decrement. The bra line will be skipped. bra DELAY_H will be decremented to 1. Not zero. Branch DELAY_H back to the start. back The first decfsz instruction will execute for 256 times. DELAY_H will be decremented to 0. End program. In total, the first decfsz instruction executes 2x256 In 36 times. times. Using Program Loops to Create Time Delays Using • Suppose DELAY_L = 0 and DELAY_H = 2. DelayLoop: DelayLoop: decfsz DELAY_L bra DelayLoop decfsz DELAY_H bra DelayLoop 1 instruction cycle (2 if skip) 2 instruction cycles 1 instruction cycle (2 if skip) 2 instruction cycles • The first two lines will run for 256 times, lasting The 255*3+2 = 767 instruction cycles during each loop. • The last two lines will run for 2 times, lasting 3+2 = 5 The instruction cycles. instruction • There are 2 loops (set by DELAY_H). There • The whole delay loop will run for 767*2+5 = 1539 The instruction cycles. instruction • If clock frequency = 4MHz (instruction freq. = 1MHz), If 37 the whole loop lasts 1.539 msec. the 4. Subroutine and Stack 4. 38 Subroutine Subroutine • A subroutine is a sequence • e.g., Lab 1 subroutine of instructions that can be called from different places in a program. in • Two reasons for creating Two subroutines: subroutines: – The problem is too big: Easier The to divide the problem into smaller sub-problems – There are several places in a There program that need to perform the same operation. the 39 Subroutine Subroutine • Subroutine is similar to branching. The Subroutine difference is that PIC needs to return to the main program where the subroutine was called. was...
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