Problem 13-2 - Example 13-2 An air-water heat exchanger has an effectiveness of 0.65 Using data on the figure below find T4 Solution We need to

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Example 13-2 An air-water heat exchanger has an effectiveness of 0.65. Using data on the figure below, find T 4 . Solution: We need to find the minimum heat capacity ratio to use in the effectiveness calculation. For the hot side (air) 1 1 H V m v = ± ± 3 1 ft volume(Air, 150, 14.7) 15.4 lbm vT P == = = 3 3 ft 300 lbm min 19.5 ft min 15.4 lbm H m ± To find , pH c , assume T 2 = 60°F
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o 12 150 60 105 F 22 ave TT T + + == = , Btu cp(Air, 105) 0.24 lbm R pH cT = , lbm Btu Btu 19.5 0.24 4.68 min lbm R min R HH p H Cm c ⎛⎞ = ⎜⎟ ⎝⎠ ± On the cold side (water), to find , pC c , assume T 4 = 70°F o 34 50 70 60 F ave T + + = , Btu cp(water, 60, 14.7) 0.999 lbm R P = = , lbm Btu
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This homework help was uploaded on 04/07/2008 for the course MANE 4010 taught by Professor Kaminski during the Spring '08 term at Rensselaer Polytechnic Institute.

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Problem 13-2 - Example 13-2 An air-water heat exchanger has an effectiveness of 0.65 Using data on the figure below find T4 Solution We need to

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