Unformatted text preview: erval, and the equation have a solution. Function
is continuous on interval −1, 0
and changes sign between 1 and 0 so it has to
be equal to zero somewhere within that
interval, and the equation have a solution. 2. Use the definition of a derivative to find the
derivative of: 2. Use the definition of a derivative to find the
derivative of: =
= lim
→ = +2
1
ℎ +ℎ+2
= lim
→ 1
ℎ − + ℎ + 4 + 2ℎ + 4 + 4ℎ −
= lim
→ +2 −4 −4 1
ℎ + 2ℎ + 4ℎ
ℎ = lim ℎ + 2 + 4 = 2 + 4
→ = lim
→ +3
1
ℎ +ℎ+3
= lim
→ 1
ℎ − + ℎ + 9 + 2ℎ + 6 + 6ℎ −
= lim
→ +3 −6 −9 1
ℎ + 2ℎ + 6ℎ
ℎ = lim ℎ + 2 + 6 = 2 + 6
→...
View
Full
Document
 Fall '12
 Dr.Zarret
 Calculus, Geometry, Intermediate Value Theorem, lim, Continuous function

Click to edit the document details