{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

SAMPLE_PART_C

# The test is that at 05 the same mean salary is 60000

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: your Part B to the project. You will label the Mean as “x”, and the Standard Deviation as “s”. Once you have this data, please go to the next row below: HYPOTHESIS TEST There is a sample of 5 salaries (\$27,000; \$45,000; \$47,000; \$57,438; \$90,000). The test is that at α = .05 the same mean salary is \$60,000. Step 1: State the hypothesis H₀: µ = \$60,000 Hₐ:µ ! \$60,000 This is a two ­tailed test Step 2: Specify the level of significance: α = .05 Step 3: Identify the degrees of freedom: Sample size n = 5 Okay…. Now we are ready to start the Hypothesis test  For this part, you will take the values and plug them in to each step. Step 1) Notice that the 60,000 was what the student set the “u” equal to and not equal to. Use your value here for “u”  Step 2) I recommend using the same value of “alpha” of 0.5 Step 3) Degrees of freedom is found by taking the sample size and subtracting 1 d.f. = n – 1 d.f. = 4 Step 4: Determine the critical values: With α = .05 and 4 degrees of freedom, the critical values is t = 2.776 Step 5: Determine the rejection regions: t <  ­2.776 and t > 2.776 Step 6: Find the standardized statistic: t = (ẍ - µ) / (s / √n) t = (53,348 - 60000) / (21247.92/√5) t≈  ­0.7 Step 7: Draw a conclusion: Because the value t =  ­0.7 is not less than  ­2.776 or greater than 2.776, then it is not in the rejection region. Therefore, we fail to re...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern