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Homework_1 - Alfonso, Noel Homework 1 Due: Sep 13 2007,...

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Alfonso, Noel – Homework 1 – Due: Sep 13 2007, 9:00 am – Inst: Dale Gary 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – Fnd all choices before answering. The due time is Central time. 001 (part 1 of 2) 15 points Consider three force vectors ~ F 1 , ~ F 2 , and ~ F 3 . The vector ~ F 1 has magnitude F 1 = 52 N and direction θ 1 = 160 ; the vector ~ F 2 has mag- nitude F 2 = 35 N and direction θ 2 = - 140 ; and the vector ~ F 3 has magnitude F 3 = 30 N and direction θ 3 = 120 . All the direction an- gles θ are measured from the positive x axis: counter-clockwise for θ > 0 and clockwise for θ < 0. What is the magnitude F of the net force vector ~ F = ~ F 1 + ~ F 2 + ~ F 3 ? Correct answer: 93 . 1364 N. Explanation: In components, each force vector is F 1 ,x = F 1 × cos θ 1 = - 48 . 864 N , F 1 ,y = F 1 × sin θ 1 = 17 . 785 N , F 2 ,x = F 2 × cos θ 2 = - 26 . 8116 N , F 2 ,y = F 2 × sin θ 2 = - 22 . 4976 N , F 3 ,x = F 3 × cos θ 3 = - 15 N , F 3 ,y = F 3 × sin θ 3 = 25 . 9808 N , and therefore the net force is F x = F 1 ,x + F 2 ,x + F 3 ,x = - 90 . 6756 N , F y = F 1 ,y + F 2 ,y + F 3 ,y = 21 . 2682 N . Consequently, the magnitude
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This note was uploaded on 04/07/2008 for the course MATH 112 taught by Professor Levy during the Spring '08 term at NJIT.

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Homework_1 - Alfonso, Noel Homework 1 Due: Sep 13 2007,...

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