Lecture 17

# Bermel 3h 100 f solution 9h 100 f equivalent circuit

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Unformatted text preview: . Bermel 3H 100 µF Solution 9H 100 µF • Equivalent circuit given above 2/20/2012 ECE 201-4, Prof. Bermel Power & Energy in Capacitors • Instantaneous power given by: = = ∙ = • Energy stored over a time interval [to, t1] is: = 2/20/2012 1 = 2 1 = 2 = − − ECE 201-4, Prof. Bermel Example 2 What is the current flow in this circuit as a function after the switch is closed at time t=0? What is the energy stored up to time t? 3 kΩ 12 V + - 100 µF 2/20/2012 200 µF ECE 201-4, Prof. Bermel Solution 3 kΩ 12 V + - 200 µF 100 µF Applying KVL: 12 = 3 Ω + /(100 + 200 = 12 − 2/20/2012 = 12 − /(300 300 3Ω ) = ECE 201-4, Prof. Bermel 3Ω ) Solution • Use separation of variables and the following rules: − = +1 = ln ln − ln 2/20/2012 − ln =...
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## This note was uploaded on 11/22/2013 for the course ECE 201 taught by Professor All during the Spring '08 term at Purdue.

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