Lecture 17 - ECE 201 Section 4 Lecture 17 Prof Peter Bermel...

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ECE 201, Section 4 Lecture 17 Prof. Peter Bermel February 20, 2012
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Capacitor “Recap” Capacitors have voltage drop proportional to stored charge: Q=CV, where C is capacitance Current flow given by: g = = ³ For N capacitors in parallel: ³ µ¶ = · ³ ¸ ¹ ¸º» For N capacitors in series: 1 ³ µ¶ = · 1 ³ ¸ ¹ ¸º» 2/20/2012 ECE 201-4, Prof. Bermel C N C 1 C C N C 1
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Capacitor Division Rules For N capacitors in parallel: g G = g ± , ² G = ³ G ³ ´µ ² ± For N capacitors in series: ² G = ² ± , g G = ³ ´µ ³ G g ± 2/20/2012 ECE 201-4, Prof. Bermel C N C 1 C N C 1 I N I 1 I o
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Example 1 What is equivalent capacitance and inductance of this 2-terminal circuit? 2/20/2012 ECE 201-4, Prof. Bermel 100 μ F 200 μ F 12 H 3 H 1 H 6 H 600 μ F 200 μ F
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Solution For inductance: g = 6 + ² ²³ + ² ²´µ ¶² For capacitance: · = ² ³¸¸ + ² ¹¸¸ + ² ²¸¸´³¸¸ ¶² 2/20/2012 ECE 201-4, Prof. Bermel 200 μ F 100 μ F 12 H 3 H 1 H 6 H 600 μ F 200 μ F
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Solution Equivalent circuit given above 2/20/2012 ECE 201-4, Prof. Bermel 100 μ F 9 H
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