{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Lecture 17 - ECE 201 Section 4 Lecture 17 Prof Peter Bermel...

Info icon This preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon
ECE 201, Section 4 Lecture 17 Prof. Peter Bermel February 20, 2012
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Capacitor “Recap” Capacitors have voltage drop proportional to stored charge: Q=CV, where C is capacitance Current flow given by: g = = ³ For N capacitors in parallel: ³ µ¶ = · ³ ¸ ¹ ¸º» For N capacitors in series: 1 ³ µ¶ = · 1 ³ ¸ ¹ ¸º» 2/20/2012 ECE 201-4, Prof. Bermel C N C 1 C C N C 1
Image of page 2
Capacitor Division Rules For N capacitors in parallel: g G = g ± , ² G = ³ G ³ ´µ ² ± For N capacitors in series: ² G = ² ± , g G = ³ ´µ ³ G g ± 2/20/2012 ECE 201-4, Prof. Bermel C N C 1 C N C 1 I N I 1 I o
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Example 1 What is equivalent capacitance and inductance of this 2-terminal circuit? 2/20/2012 ECE 201-4, Prof. Bermel 100 μ F 200 μ F 12 H 3 H 1 H 6 H 600 μ F 200 μ F
Image of page 4
Solution For inductance: g = 6 + ² ²³ + ² ²´µ ¶² For capacitance: · = ² ³¸¸ + ² ¹¸¸ + ² ²¸¸´³¸¸ ¶² 2/20/2012 ECE 201-4, Prof. Bermel 200 μ F 100 μ F 12 H 3 H 1 H 6 H 600 μ F 200 μ F
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Solution Equivalent circuit given above 2/20/2012 ECE 201-4, Prof. Bermel 100 μ F 9 H
Image of page 6
Image of page 7
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern