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HW4Solutions - SOLUTIONS HW4: Q24-14) The potential...

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Unformatted text preview: SOLUTIONS HW4: Q24-14) The potential difference remains constant as the capacitor is connected to a battery. The capacitance changes back its value without dielectric, K C C = . The charge on the plates decreases to K Q Q = . The energy that is stored changes from 2 2 V C U = to 2 2 2 2 V K C V C U = = . The electric field remains the same as E = V/d and the potential difference remains constant. Q24-15) If Q does not change, 2 2 2 2 KC Q C Q U = = , if V does not change, 2 2 2 2 V KC CV U = = . P21-18) Q = 560 m C = Q1 + Q2. d = 1.10m. F = 22.8N, repulsive. As the force is repulsive, we know that both charges are either positive or negative. From just this information, we cannot say for sure which one it is as the force only contains the product of the two charges. C or C F d Q Q Q Q Q C or C F d Q Q Q Q QQ F d N d Q Q Q d Q Q F 6 6 2 2 6 6 2 2 2 2 2 2 10 5 . 554 10 5 . 5 ) 4 ( 4 2 2 1 10 5 . 5 10 5 . 554 ) 4 ( 4 2 2 2 2 ) 4 ( 8 . 22 4 2 ) 2 ( 4 2 1 = =...
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HW4Solutions - SOLUTIONS HW4: Q24-14) The potential...

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