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Unformatted text preview: of the sample, we have m = water V . For the density of the sample we have = m / V = ( m / m ) water = [(63.5 g)/(63.5 g 56.4 g)](1.00 10 3 kg/m 3 ) = 8.94 10 3 kg/m 3 . From the table of densities, the most likely metal is copper . 1345. If we ignore viscosity, we can use Bernoullis equation. We choose the initial point at the top of the water, where the velocity is essentially zero, and the final point at the hole. Thus we have P 1 + ! v 1 2 + gy 1 = P 2 + ! v 2 2 + gy 2 ; P atm + 0 + gh = P atm + ! v 2 2 + 0, which gives v 2 = (2 gh ) 1/2 = [2(9.80 m/s 2 )(4.6 m)] 1/2 = 9.5 m/s ....
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This note was uploaded on 04/07/2008 for the course PHY 113 taught by Professor Jordan during the Spring '08 term at Rochester.
 Spring '08
 Jordan

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