# 8.3 - 8.3(a Plot of peak hour traffic vs daily traffic 1.6...

This preview shows pages 1–2. Sign up to view the full content.

8.3 (a) Plot of peak hour traffic vs daily traffic 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 01234567 Daily traffic (1000 vehicles) Peak hour traffic (1000 vehicles) (b) Let X be the daily traffic volume and Y the peak hour traffic volume, both in thousand vehicles. By Eq. 8.9, the correlation coefficient between X and Y is estimated by y x n i i i s s y x n y x n = = 1 1 1 ˆ ρ With n = 5, = 25.54, = n i i i y x 1 x = 1.02, y = 4.72, and the sample standard deviations s x = 0.303315018 while s y = 1.251798706, ˆ = (1/4)(1.468 / 0.379689347) 0.967 (c) x i y i x i y i x i 2 i i x y β α ˆ ˆ ' + = (y i – y i ’) 2 5 1.2 6 25 1.085577537 0.0130925 4.5 1 4.5 20.25 0.968474793 0.00099384 6.5 1.4 9.1 42.25 1.436885769 0.00136056 4.6 0.9 4.14 21.16 0.991895341 0.00844475

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
3 0.6 1.8 9 0.61716656 0.00029469 Sum 23.6 5.1 25.54 117.66 0.02418634 Mean 4.72 1.02 Since we know the total (daily) traffic count (X), and want a probability estimate about the peak hour traffic (Y), we need the regression of Y on X, i.e. the best estimates of
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

8.3 - 8.3(a Plot of peak hour traffic vs daily traffic 1.6...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online