2.8 - ⏐ concrete production not feasible at site = P(E 2...

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2.8 P(E 1 ) = 0.8; P(E 2 ) = 0.7; P(E 3 ) = 0.95 P(E 3 2 E ) = 0.6; assume E 2 and E 3 are statistically independent of E 1 (a) A = (E 2 E 3 ) E 1 B = or E E E 1 3 2 ) ( 2 E 3 E 1 E (b) P(B) = P( 1 E 2 E 3 E ) = P( 1 E ) + P( 2 E 3 E ) – P( 1 E 2 E 3 E ) = 0.2 + P( 3 E 2 E )P( 2 E ) – P( 1 E )P( 2 E 3 E ) = 0.2 + 0.4x0.3 – 0.2x(0.4x0.3) = 0.296
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Unformatted text preview: ⏐ concrete production not feasible at site) = P((E 2 ∪ E 3 ) E 1 ⏐ 2 E ) = ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( 2 2 2 3 1 2 3 2 1 2 2 1 3 2 E P E P E E P E P E P E E E P E P E E E E P = = ∪ = 0.8 x 0.6 =0.48...
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