lecture 8 - - So the number of moles are the same in dilute...

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1 Lecture 8, Oct. 16 Chapter 4. Aqueous Reactions and Solution Stoichiometry (continued) Reading: section 5 & 6
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2 Examples: 1. Calculate the molar concentration of a solution that contains 2.8g KOH in 250 ml solution. 2. What is the molarity of hydroxide ion in a 0.20M Ba(OH) 2 solution? 3. How would you prepare 250ml of 5.43 M NaCl? 4. What volume of this NaCl solution is needed to supply 10.0 g of NaCl? Dilution Problem: How many mL of concentrated H 2 SO 4 (18.0 M) are required to prepare 200 mL of 1.00 M H 2 SO 4 ? - Adding water to a solution does not change the moles of solute in the solution.
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Unformatted text preview: - So the number of moles are the same in dilute and concentrated solutions. M dilute V dilute = moles = M concentrated V concentrated 3 Solution Stoichiometry Problem: What volume of 0.215M HCl is required to react completely with 0.685 g of Ba(OH) 2 ? Titrations 4 Problem: A 10.00 ml sample of iron(II) sulfate required 18.58 ml of 0.0238 M KMnO 4 to reach the equivalent point. What is the concentration of the FeSO 4 ? The reaction is 10 FeSO 4 + 2 KMnO 4 + 8H 2 SO 4 5Fe 2 (SO4) 3 + 2MnSO 4 + K 2 SO 4 + 8H 2 O...
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lecture 8 - - So the number of moles are the same in dilute...

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