Lab 2 lab report - Matthew Mueller Aug. 31, 2007 CHEM...

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Unformatted text preview: Matthew Mueller Aug. 31, 2007 CHEM 207-01A PROPER USE OF LABORATORY GLASSWARE AND PREPARATION OF SOLUTIONS Objective This lab involved in the first part the creation of a 2.5 - 10 3 M K 3 Fe(CN) 6 solution and then the dilution of that solution into a 2.5 - 10 4 M K 3 Fe(CN) 6 solution. In the second part a basic titration of 0.1 M NaOH into 0.1 M HCl is preformed. Stoichiometry Compound Amount MW Mole Other K 3 Fe(CN) 6 .206 g 329.26 g/mole 6.26 - 10 4 mol NaOH (aq) 50 mL @ .1 M 40.00 g/mole 5.00 - 10 3 mol HCl (aq) 25 mL @ .1 M 36.46 g/mole 2.50 - 10 3 mol Procedure Observations 1. Calculate the amount of K 3 Fe(CN) 6 (329.26 g/mole) needed to prepare a 250 mL, 2.5 - 10 3 M solution. 2.5 - 10 3 M .250 L (329.26 g/mole) = .206 g 2. Tare a 50 mL beaker and add the appropriate amount of K 3 Fe(CN) 6 . Record mass to 3 decimal places. Mass (K 3 Fe(CN) 6 ) = .206 g 3. Add a little water to the 50 mL beaker and transfer contents to a 250 mL volumetric flask....
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This note was uploaded on 04/08/2008 for the course CHEM 207 taught by Professor Richardson during the Fall '08 term at University of Louisville.

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Lab 2 lab report - Matthew Mueller Aug. 31, 2007 CHEM...

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