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Unformatted text preview: pressure of 200 psia, Since the system is a piston cylinder device the final pressure will be the same as the initial pressure, thus P 2 = 200 psia and also T 2 = 100 o F. With these two properties is possible to determine the final specific volume, which is v 2 = 0.0161 ft 3 /lbm. Therefore the final volume of the system is V 2 = 0.0161 ft 3 3 35 Given : Water, m = 1 lbm; V = 2 ft 3 ; P = 100 psia Find: U and H. Solution: For v = 2 ft 3 /lbm, P = 100 psia, the state of the system is saturated vaporsaturated liquid mixture. Thus h = 697.6 Btu/lbm and u = 660.6 Btu/lbm, which results in a total enthalpy and internal energy of H = 697.6 Btu U = 660.6 Btu 3/8 3 53 4/8 3 58 5/8 3 62 6/8 7/8 8/8...
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This note was uploaded on 04/07/2008 for the course ME 232 taught by Professor Monefort during the Spring '08 term at Western Michigan.
 Spring '08
 Monefort

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