lecture 7 Power, Transmission_v.2

# 30203 400 240 ga gb lz 1 2 z 02 z 0 2

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: •  (Ohm’s Law) V=Iz Power ﬂows and Kirchoﬀ’s Laws za P1 I1 P2 I2 zb Ia za = Ib zb = V (from K.V.) Ia za = (I Ia )zb (from K.C.) Therefore Ia = Pz = Ia V = zb za +zb zb za +zb I. IV = zb za +zb P. GA GB LZ 1 2 Z = 0.2 Z = 0. 2 Gc Lx 3 Gd LY Suppose Gb and Ly want to contract for 400 MW. The power ﬂows along both 13 and 123 according to K. P123= [0.2/(0.2+0.3)] 400 = 160 P13= [0.3/(0.2+0.3)] 400 = 240 GA GB LZ 1 2 Z = 0.2 Z = 0. 2 Gc Lx 3 Gd LY Suppose Gb and Ly want to contract for 400 MW. P123= [0.2/0.5] 400 = 160, P13= [0.3/0.5] 400 = 240. Suppose Gd and Lz want to contract for 200 MW. P31= [0.3/0.5] 200 = 120, P321= [0.2/0.5] 200 = 80. Total ﬂows add: P13 = 240 - 120 = 120, P12=P23= 180. G2 Bus 2 Bus 1 Bus 3 G1 L Line Capacity Impedance 1- 2 100 .1 2- 3 220 .1 1- 3 300 .1 Ignore reacTve power Assume resistance <<< reacTve No losses P13 : 1/3 goes thru 1 - > 2 - > 3, 2/3 goes...
View Full Document

## This document was uploaded on 12/08/2013.

Ask a homework question - tutors are online