lecture 7 Power, Transmission_v.2

30203 400 240 ga gb lz 1 2 z 02 z 0 2

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Unformatted text preview: •  (Ohm’s Law) V=Iz Power flows and Kirchoff’s Laws za P1 I1 P2 I2 zb Ia za = Ib zb = V (from K.V.) Ia za = (I Ia )zb (from K.C.) Therefore Ia = Pz = Ia V = zb za +zb zb za +zb I. IV = zb za +zb P. GA GB LZ 1 2 Z = 0.2 Z = 0. 2 Gc Lx 3 Gd LY Suppose Gb and Ly want to contract for 400 MW. The power flows along both 13 and 123 according to K. P123= [0.2/(0.2+0.3)] 400 = 160 P13= [0.3/(0.2+0.3)] 400 = 240 GA GB LZ 1 2 Z = 0.2 Z = 0. 2 Gc Lx 3 Gd LY Suppose Gb and Ly want to contract for 400 MW. P123= [0.2/0.5] 400 = 160, P13= [0.3/0.5] 400 = 240. Suppose Gd and Lz want to contract for 200 MW. P31= [0.3/0.5] 200 = 120, P321= [0.2/0.5] 200 = 80. Total flows add: P13 = 240 - 120 = 120, P12=P23= 180. G2 Bus 2 Bus 1 Bus 3 G1 L Line Capacity Impedance 1- 2 100 .1 2- 3 220 .1 1- 3 300 .1 Ignore reacTve power Assume resistance <<< reacTve No losses P13 : 1/3 goes thru 1 - > 2 - > 3, 2/3 goes...
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