Chm_205_Exam_2_Spr_2011

1 e 2 p ts w h a t is th e n u m e r ic a l v a lu e

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: . ( 2 p ts ) W h a t is th e n u m e r ic a l v a lu e fo r K c fo r : B (g ) + 3 C (g ) 2 A (g ) 1 f. ( 2 p ts ) W h a t w o u ld h a p p e n to [A ] a n d [B ] if s o m e C ( g ) w e r e a d d e d to th e e q u ilib r iu m m ix tu r e a n d a llo w e d to r e e q u ilib r a te ? C ir c le y o u r c h o ic e . ( a ) [A ] w o u ld : in c r e a s e d e c r e a s e s ta y th e s a m e 5 . ( 1 1 p ts ) W r ite a n a r r o w u p to in d ic a te in c r e a s e s , a r r o w d o w n fo r d e c r e a s e s a n d a d a s h ( - ) to s ig n ify n o c h a n g e th a t o c c u r s to th e e n titie s lis te d a c r o s s th e to p r o w w h e n th e c h a n g e s in th e le ft c o lu m n a r e a p p lie d to th e e x o th e r m ic r e a c tio n , k n o w n to fo llo w fir s t o r d e r k in e tic s : 2 A (g ) B (g ) ( b ) [B ] w o u ld : in c r e a s e d e c r e a s e s ta y th e s a m e K in e tic s r e g io n k fw d R a te 2 . ( 2 p ts ) W r ite a K p e x p r e s s io n fo r th e e q u ilib r iu m : A l2 O 3 ( s ) + 3 C O ( g ) 2 A l( s ) + 3 C O 2 ( g ) Δ H < 0 a n d ra te = k [A ] T e m p in c r e a s e d V o lu m e in c r e a s e d S o m e B re m o v e d A t e q u ilib r iu m Kc [B ] 6 . ( 4 p ts ) C ir c le a ll o f th e fo llo w in g e q u a tio n s th a t d e s c r ib e th e r e la tio n s h ip b e tw e e n k in e tic s a n d e q u ilib r iu m k fwd a. k fwd = k rev b. Kc = c. € rate fwd = raterev d. K c = k[ A]0, 1, or 2 k rev 1 2 d . ( 2 p ts ) R e fe r r in g to th e ta b le , w h ic h w e a k b a s e w o u ld is th e s tr o n g e s t o f th e th r e e ? 7 . ( 1 p t) W h ic h s o lu tio n is m o s t a c id ic ? € A . p H = 8 .2 € 1 2 c . ( 2 p ts ) W h a t is th e v a lu e o f K a fo r H C ? B . [O H -] = 9 .2 x 1 0 -3 € C . [H 3 O + ] = 4 .0 x 1 0 -5 D . p O H = 1 1 .8 8 - ] in a s o lu tio n w ith p H = 9 .7 7 ? 8 . ( 2 p ts ) W h a t is [O H 1 3 . A c e tic a c id , H C 2 H 3 O 2 h a s a K a = 1 .8 x 1 0 -5 . 1 3 a . ( 3 p ts ) D e te r m in e th e p H o f a 0 .2 3 0 m o la r s o lu...
View Full Document

This note was uploaded on 12/08/2013 for the course CHM 205 taught by Professor Mattson during the Fall '13 term at Creighton University.

Ask a homework question - tutors are online