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Unformatted text preview: 1) Ca++ Ions N e r v e I m p u l s e 2) Vesicle Released 4 c ) R e u p t a k e COMT Inactivation 4b) Diffusion 5) Bound Receptors 5) Unbound Receptors Blood 3) [NE] in junction 4a) [NE] Available Presynaptic Axon Postsynaptic Dendrite Michael Greer EBME 202 - HW #1 #1) Incident NAP a) 20 Hz b) 60 Hz Ca++ Influx into cell (Use integration function; or assume 50 Ca++ ions enter cell per AP) but making sure not to go beyond supply o extracellular Ca++ a) 1000 Ca++ b) 3000 Ca++ Available NE = Release of NE into junction (Related to Ca++ in linear manner according to graph # 3, therefore assume 1 NE enter junction per 2 Ca++ but only to limit of NE available) a) 500 NE b) 1500 NE # of NE molecules available for binding 4c Reuptake Reuptake relates linearly to amount of NE in junction. According to my research 50-80% of NE is removed from junction via reuptake. Assuming 50%, NE lost is a) 250 NE b) 750 NE a) 250 NE lost b) 750 NE lost 4a COMT COMT relates linearly to amount of NE in junction assuming there is enough COMT to handle the NE. Therefore, we assume that about 10% NE is lost thru COMT COMT deactivation NE lost = 10% X NE a) 50 NE lost b) 150 NE lost [COMT] = 2.2 X 10^-3 mol/L. Giving about 35 COMT in the volume provided (6.4X10^-20 L)....
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This homework help was uploaded on 04/08/2008 for the course EBME 202 taught by Professor Cechner during the Spring '07 term at Case Western.
- Spring '07