# chap34 - 34.1 If up is the y-direction and right is the x...

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Unformatted text preview: 34.1: If up is the y +-direction and right is the x +- direction, then the object is at ), , ( at is ), , ( 2 y x P y x- ′-- and mirror 1 flips the y-values, so the image is at ) , ( y x which is . 3 P ′ 34.2: Using similar triangles, m. 3.24 m 0.350 m 0.350 m 28.0 m 040 . mirror tree mirror tree mirror tree mirror tree = + = = ⇒ = d d h h d d h h 34.3: A plane mirror does not change the height of the object in the image, nor does the distance from the mirror change. So, the image is cm 2 . 39 to the right of the mirror, and its height is cm. 85 . 4 34.4: a) cm. . 17 2 cm . 34 2 = = = R f b) If the spherical mirror is immersed in water, its focal length is unchanged—it just depends upon the physical geometry of the mirror. 34.5: a) b) cm, . 33 cm 5 . 16 1 cm . 22 2 1 1 1 1 = ′ ⇒- = ′ ⇒ = ′ + s s f s s to the left of the mirror. cm, 20 . 1 cm 16.5 cm 33.0 cm) 600 . (- =- = ′- = ′ s s y y and the image is inverted and real. 34.6: a) b) cm, 60 . 6 cm 5 . 16 1 cm . 22 2 1 1 1 1- = ′ ⇒-- = ′ ⇒ = ′ + s s f s s to the right of the mirror. cm, 240 . cm 16.5 cm) .60 6 ( cm) 600 . ( =-- = ′- = ′ s s y y and the image is upright and virtual. 34.7: m. 75 . 1 m 10 58 . 5 1 m 75 . 1 1 1 1 1 1 10- = ′ ⇒ ×- = ′ ⇒ = ′ + s s f s s m. 10 13 . 2 ) m 10 6794 )( 10 14 . 3 ( 10 14 . 3 10 58 . 5 75 . 1 4 3 11 11 10--- × = × × = = ′ ⇒ × = ×- = ⇒ my y m 34.8: cm 40 . 1 cm . 21 1 cm 00 . 3 2 1 1 1 1 , cm 00 . 3- = ′ ⇒-- = ′ ⇒ = ′ +- = s s f s s R (in the ball). The magnification is . 0667 . cm . 21 cm 40 . 1 =-- = ′- = s s m 34.9: a) . Also . 1 1 1 1 1 1 s f f s s m f s sf s fs f s s f s f s s- = ′- =- = ′ ⇒- =- = ′ ⇒ = ′ + b) For , , ′ ⇒ s f s f so the image is always on the outgoing side and is real. The magnification is , <- = s f f m since . s f < c) For , 1 2 =- < ⇒ ≥ f f m f s which means the image is always smaller and inverted since the magnification is negative. For . 1 2 = ⇒ <- < ⇒ < < f f m f f s f s f d) Concave mirror: , < ′ ⇒ < < s f s and we have a virtual image to the right of the mirror. , 1 = f f m so the image is upright and larger than the object. 34.10: For a convex mirror, . < +- =- = ′ ⇒ < f s f s f s sf s f Therefore the image is always virtual. Also , + =--- =- = s f f s f f s f f m so the image is erect, and , since 1 f s f m + < so the image is smaller. 34.11: a) b) . , for < ′ s f s s c) . for f s s < < < ′ d) If the object is just outside the focal point, then the image position approaches positive infinity. e) If the object is just inside the focal point, the image is at negative infinity, “behind” the mirror. f) If the object is at infinity, then the image is at the focal point....
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## This homework help was uploaded on 04/08/2008 for the course PHY 205 taught by Professor Nearing during the Fall '07 term at University of Miami.

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chap34 - 34.1 If up is the y-direction and right is the x...

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