Ch15p - Chapter 15 Exercise Solutions EX15.1 For the...

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Chapter 15 Exercise Solutions EX15.1 For the circuit shown in Figure 15.7 3 1 2 dB f RC π = or () 6 3 3 11 3.979 10 2 24 01 0 dB RC f == = × × For 75 K R = Then 11 5.31 10 53.1 pF C = 3 4 We have 1.414C 75.1 pF 0.707C 37.5 pF C C EX15.2 1 C eq f CR = or ( ) 56 10 20 10 0.5 pF ce q C fR C × = EX15.3 Low-frequency gain: 1 2 30 6 5 C T C =− ( ) 31 2 2 33 12 100 10 5 10 6.63 kHz 2 21 0 C dB dB F fC ff C ×× = × EX15.4 0 6 3 0 1 23 6.13 10 2 ( 1 5 1 0 ) 3 f RC RC f ππ = = × × Let 0.001 μ F1 n F C Then 6.13 k R so 2 84 9 k RR Ω EX15.5 0 0 4 2 22 1 0.02 F 2 800 10 2 2 10 20 k RC f R CC R μ = = = EX15.6
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() 1 12 1 1 11 2( 1 2 ) 20 22 0 1 2 40 10 4 k TH H R VV RR R R ⎛⎞ = ⎜⎟ + ⎝⎠ = + += = EX15.7 [] 1 1 2 1 2 0.10 10 10 20 0 0 1 9 9 0.10 1 1 1 . 0 0 5 V 199 on 0.1 10 0.7 0.7 0.1 43 k 0.2 42.9 k TH TL H L SR E F REF S REF HB E R V V R R R V R V I R R R γ −= + =− + = = = + =+ = −− = + = Ω EX15.8 At 0, t = let 0 5 v so 2.5. X v For 0 t > 10 2.5 10 exp X X t v r − − When 5.0, X v = output switches 1 1 1 5.0 10 12.5 exp 10 5 5.0 exp 12.5 12.5 12.5 12.5 exp ln 0.916 5.0 5.0 X X XX X t r t r t tr r = =⋅ = During the next part of the cycle 5 5 5 exp X X t v r =− + When 2.5, X v output switches
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() ( ) ( ) 2 2 2 22 12 36 4 2.5 5 10 exp 52 . 5 2 . 5 exp 10 10 10 10 exp ln 1.39 2.5 2.5 1 Period 0.916 1.39 2.31 Frequency 2.31 50 10 0.01 10 5 10 s 866 Hz Du X X XX X X X t r t r t tr r tt T r r r rf −− ⎛⎞ −= + ⎜⎟ ⎝⎠ = += =⋅ = =+== + = = ⎡⎤ ⎣⎦ × = × = ( ) 1 0.916 ty cycle 100% 100% Duty cycle 39.7% 0.916 1.39 t tt =×= × = ++ EX15.9 a. [] 1 0 1 6 6 6 10 12 1.2 V 10 90 0.10 0.7 1 1/ 12 ln ln 11 ( 0 . 1 0 ) 50 10 ln 1.18 (0.162) 50 10 3.09 k (0.1 10 )(0.162) X Y P rR C R vv RR R VV Tr r r γ β = == = + + + ⎢⎥ = = × = × b. Recovery time ( 1.2 ) exp XP P X t vV V r =+ When , X = 2 =
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() ( ) 2 2 2 36 4 2 0.7 12 1.2 12 exp 12 0.7 exp 0.856 13.2 1 ln 0.155 0.856 3.09 10 0.1 10 3.09 10 48.0 s X X XX X t r t r tr r rt μ −− ⎛⎞ =+ − − ⎜⎟ ⎝⎠ −= = == ×= × = EX15.10 6 1.1 RC 75 10 T T = Let 10 nF C = Then 6 9 75 10 6.82 K 1.1 10 10 R × × EX15.11 ( ) 11 802 Hz 0.693 2 0.693 20 2 80 10 0.01 10 20 80 Duty cycle 100% 100%
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This homework help was uploaded on 02/10/2008 for the course ECE 138 taught by Professor N/a during the Spring '08 term at CSU Fresno.

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Ch15p - Chapter 15 Exercise Solutions EX15.1 For the...

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