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# Ch13s - Chapter 13 Problem Solutions 13.1 13.2 13.3(a g m1...

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Chapter 13 Problem Solutions 13.1 Computer Simulation 13.2 Computer Simulation 13.3 (a) ( ) 1 2 4 6 d m o o i A g r r R = 1 1 2 2 2 4 4 2 6 6 1 7 7 6 1 6 20 0.769 / 0.026 80 4 20 80 4 20 (1 ) (120)(0.026) 15.6 0.2 ( ) 0.6 0.030 20 (120)(0.026) 104 0.030 C m T A o C A o C i n BE C I g mA V V V r M I V r M I R r R r r k V on I mA R r k π π π π β = = = = = Ω = = = Ω = + + = = Ω = = = = Ω Then 6 104 (121) 20 15.6 1.16 i R M = + ⎤ ⇒ Ω Then ( ) 769 4 4 1.16 565 d d A A = = Now 1 7 7 7 7 7 6 1 7 1 1 7 6 6 1 7 6 ( ) (1 ) and o c o n b o n o c o n n o b b i R V I r I r r I R r V R r I I R r R π π β β β β = − = − = − + = − + = + Then 7 1 2 1 6 1 7 7 7 (1 ) 80 400 0.2 o n n o v o i A o C V r R A V R R r V r k I π β β + = = + = = = Ω So 2 2 (120)(121)(400) 20 2813 1160 20 15.6 v v A A = = − + 6 2 Overall gain (565)( 2813) 1.59 10 d v A A A = = = − × (b) 1 2 id R r π = and 1 (80)(0.026) 104 0.020 r k π = = Ω 208 id R k = Ω (c) 1 and (10)(1 2813) 28,140 2 PD M eq M f C pF R C π = = + = 2 4 6 6 12 4 4 1.16 0.734 1 7.71 2 (0.734 10 )(28,140 10 ) eq o o i PD R r r R M f Hz π = = = Ω = = × ×

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