Ch13p - Chapter 13 Exercise Solutions EX13.1 I C1 = I C 2...

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Chapter 13 Exercise Solutions EX13.1 1 2 1 2 1 2 9.5 A 9.5 A 0.0475 A 47.5 nA 200 C C B B B B I I I I I I μ μ μ = = = = = = EX13.2 17 13 16 16 5 0.6 0.6 ( 5) 0.22 mA 40 0.75 (0.75)(0.22) 0.165 mA 0.165 (0.165)(0.1) 0.6 200 50 0.000825 0.01233 13.2 A REF C C B REF C C I I I I I I μ − − = = = = = = + = + = + = EX13.3 3 14 0.18 10 10 exp D T V V × = 3 14 3 14 0.18 10 ln 10 0.18 10 (0.026)ln 10 0.6140 D T D V V V × = × = = 2 1.228 V BB DD V V = 14 20 14 2 exp 0.6140 3 10 exp 0.026 BB C C S T V I I I V / = = = × 14 20 0.541 mA C C I I = = EX13.4 6 100 10.5 M 0.0095 o r = Ω Then, using results from Example 13.4
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