Ch14s - Chapter 14 Problem Solutions 14.1 Ad = vo =-80 vi...

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Chapter 14 Problem Solutions 14.1 80 (max) 4.5 (max) 56.25 mV o d i o i v A v v v = = − = = So 56.25 (max) 39.77 mV 2 i rms v = = 14.2 (a) 2 4.5 0.028125 mA 160 4.5 4.5 mA 1 L i i = = = = Output Circuit 4.528 mA = 4.5 0.05625 V 80 o i i v v v A = − = = − (b) 4.5 15 mA (min) 300 o o L L L v i R R R = = = Ω 14.3 (1) 2 V o v = (2) 2 12.5 mV v = (3) 4 2 10 OL A = × (4) 1 8 V v μ = (5) 1000 OL A = 14.4 From Eq. (14.4)
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2 1 2 1 2 1 2 3 1 2 1 2 3 3 1 2 1 2 1 / 1 1 1 / 15 1 1 1 2 10 15 1 15 1 2 10 2 10 15.0075 (0.9925) 15.12 CL oL R R A R A R R R R R R R R R R R R R = + + = + + × + + = × × = = 14.5 1 0 1 1 0 0 1 1 2 0 1 0 0 1 1 2 1 2 and so that 1 1 1 I L i L I i v v v v v v A v R R R v v A v v v R R R R R = + = − = − + = + + So 0 1 2 0 1 2 1 1 1 1 1 I L i v v R R A R R R = − + + + Then 0 1 2 0 1 2 (1/ ) 1 1 1 1 1 CL I L i v R A v R A R R R = = + + + From Equation (14.20) for L R = ∞ and 0 0 R = 0 2 (1 ) 1 1 1 1 L if i A R R R + = + a. For 1 k i R = Ω 3 3 (1/ 20) 1 1 1 1 1 100 20 100 1 10 0.05 [0.01 1.06 10 ] CL A = + + + = + × or
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