Ch11p - Chapter 11 Exercise Solutions EX11.1 vE =-VBE on vE...

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Chapter 11 Exercise Solutions EX11.1 ( ) ( )( ) 1 2 1 2 1 2 on 0.7 V 0.5 mA 10 0.5 10 5 V E BE E C C C C C C v V v I I v v v v = − = − = = = = = = EX11.2 2 1 0.99 1 exp 1 1 exp 0.99 1 exp 1 0.99 1 ln 1 119.5 mV 0.99 C Q d T d T d T d T d i I v V v V v V v V v = = + + = = = = − EX11.3 a. ( )( ) 1 2 1 2 1 0 0.7 V 0.25 8 2 V 3 V 3.7 V E RC C C EC v v v V v v v = = = Δ = = = = − = b. 1 2 1 2.5 V 3.2 V 6.2 V E EC v v v v = = = = c. 1 2 1 2.5 V 1.8 V 1.2 V E EC v v v v = = − = − = EX11.4 Let 1 , Q I mA = then 1 2 0.5 CQ CQ I I mA = = 1 2 0.5 19.23 / 0.026 m m g g mA V = = = At 2 2 2 1 , 2 c C d m C d v v A g R v = = So, ( ) 2 2 1 150 19.23 15.6 2 C C R R k = = Ω At 1 1 1 1 , 2 c C d m C d v v A g R v = = − So, ( ) 1 1 1 100 19.23 10.4 2 C C R R k = − = Ω If 10 and 10 , V V V V + = + = − dc biasing is OK. EX11.5 ( ) ( )( ) ( ) ( )( )( ) ( )( ) ( )( )( ) ( ) 0.8 12 2 0.026 2 0.0594 1 101 0.8 100 1 1 0.026 100 0.0594 1sin 59.4sin Q C T cm Q O T o cm cm I R V A I R V v A v t mV t V β β ω ω μ = = = − + + + = = − = − EX11.6
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