Ch10p - Chapter 10 Exercise Solutions EX10.1 V + - VBE ( on...

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Chapter 10 Exercise Solutions EX10.1 () 1 0 0 on 10 0.7 15 0.62 mA 0.62 22 11 75 0.604 mA BE REF REF REF VV I R I I I I β + == = ++ = EX10.2 ( ) ( ) 1 0 2 00 2 0 0 0 on 5 0.7 5 12 0.775 mA 0.775 0.7549 mA 75 1 0.02 0.7549 0.0151 mA and 4 265 k 265 0.7549 200 V 0.0151 BE REF REF REF CE CE A AA V I R I I I V II V r rI V rV V I +− −− = = Δ Δ= = Δ= Δ = Δ = = EX10.3 1 0 01 0 12 312 3 3 33 2o n 9 2 0 . 7 12 0.6333 mA 0.6333 0.6331 mA 17 5 7 6 0.6331 mA 8.44 A 16.88 A 0.222 A 1 BE REF REF REF C BB EB B E E I R I I I I I I I ββ μ + = = + =+ = = = + EX10.4 ( ) 0 0 0 ln 0.026 0.75 ln ln 3.54 k 0.025 0.025 50 . 7 5.73 k 0.75 0.025 3.54 88.5 mV REF ET TR E F EE BE BE E BE BE I IR V I VI RR I R ⎛⎞ = ⎜⎟ ⎝⎠ = = = −= = EX10.5
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() () ( ) 0 0 00 0 50 . 7 5 0.775 mA 12 ln 0.775 6 0.026 ln 16.6 A REF REF REF ET II I IR V I I μ −− = = ⎛⎞ = ⎜⎟ ⎝⎠ = EX10.6 ( ) 0 0 0 22 2 0 02 0 2 2 2 ln 0.026 0.70 ln 3.465 k 0.025 0.025 0.025 0.9615 mA/V 0.026 150 0.026 156 k 0.025 100 4000 k 0.025 || 3.47 ||156 3.39 k 14 0 0 REF EE mm T T A mE I I RR I gg V V r I V r I r Rr gR π β = = = == = = = = =+ = ( ) 0 02 0 0 0 1 0.962 3.39 17.04 M 13 0.176 A 17,040 C R dI dV dI R + ⎡⎤ ⎣⎦ = =⋅ = = EX10.7 1 01 01 02 0 1 2 01 01 01 ... ... and ... 1 11 REF R BR B BN RN B R B B B N REF I I I I III I I I I I I N N I ββ =+ + ++ = = == = = = ⎛⎞ ⎛ + =++ = + ⎜⎟ ⎜ ⎝⎠ ⎝ 01 02 0 01 So ... 1 1 1 0.90 1 1 50 1 50 0.9 1 5 0 0.9 1 15 0 1 0.9 4.55 4 REF N REF I I N I N I N N N NN = = + + + + + += =− = = EX10.8
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() 22 2 2 2 2 12 3 2 0.20 0.020 3 2 10 DS GS TN GS GS no x O n GS TN GS TN Vs a t VV V V V V C W IK V V V V L WW LL μ == −= = ⎛⎞ =− = ⎜⎟ ⎝⎠ = 2 1 1 2 11 2 0.5 0.020 3 2 25 x REF GS TN GS GS C W IV V L VV = = 31 2 3 3 2 33 10 3 7 2 0.5 0.020 7 2 1 GS GS x REF GS TN V V C W V L + = = = EX10.9 a. 2 2 0.020 0.080 1 1.5 V all transistors REF n GS TN GS GS V V V V = b. ( ) ( ) 431 44 4 4 1.5 1.5 5 2 V 21 . 5 3 . 5 V min sat and 1.5 1 0.5 So min 3.5 0.5 min 3.0 V GG SG S SGG S D S DS DS GS TN DD VVVV VVV V V s a t V V V =++ = + = = = =+ = −=− = + c. ( ) ( ) ( ) ( ) 00 40 2 0 4 02 04 0 1 2500 k 0.02 0.020 2 2 0.080 1.5 1 0.080 / 2500 2500 1 0.080 2500 505 M m mn G S T N m Rrr g r rr I g KV V g m AV RR λ + = = = = + = EX10.10 2 For : min 2 V min min 5 2 5 min 3 V DS P S DS S Qv V V v V = ( ) ( ) () ( ) 02 2 0 2 1 01 1 2 1 1 1 1 1 0.5 1 0.15 2 0.65 mA 1 0.65 0.80 1 2 0.0986 0.197 V 2 0.197 3 min 3.2 V DSS DS GS DSS P GS GS GS GS I S I I II v I v V v v v vV V V V =+= + = = =−−
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21 0, == g sg s X VV V 1 1 02 01 XX X mX VVV I gV rr =+ + (1) 11 1 01 X D g V Rr += (2) 1 01 1 01 1 Xm D Vg r V ⎛⎞ + ⎜⎟ ⎝⎠ = + 1 01 01 1 00 20 1 01 01 1 02 01 01 1 02 01 01 111 1 1 1 m X m X D m D D m D g I g VR r g R g + ==+ +− + ⎡⎤ ⎢⎥ + + ⎣⎦ + +
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01 1 00 2 0 1 11 1 For Dm Rr g r ⎛⎞ ≅+ + ⎜⎟ ⎝⎠ ± For Q 1 : () 1 1 20 . 8 2 0.197 22 0.721 mA/V DSS
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This homework help was uploaded on 02/10/2008 for the course ECE 138 taught by Professor N/a during the Spring '08 term at CSU Fresno.

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Ch10p - Chapter 10 Exercise Solutions EX10.1 V + - VBE ( on...

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