Ch09p - Chapter 9 Exercise Solutions EX9.1 Av = -15 = - R2...

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 9 Exercise Solutions EX9.1 () 2 1 12 1 15 20 K 15 15 20 300 K v i R A R RR R R =− == = EX9.2 33 2 14 1 11 23 3 4 44 4 4 We can write 1 10 k Want 50 Set 50 k 50 5 1 5 50 19 8 6.25 k CL CL CL R A R AR R R A R R R ⎛⎞ + ⎜⎟ ⎝⎠ Ω = = Ω + += EX9.3 We have 2 1 2 1 1 1 CL d R A R R ++ 1 25 k i Ω Let 2 1 R x R = 3 3 3 3 2 2 12 1 51 0 1.0002 0 12 1.0002 0 12.0024 2.4 10 12.0024 12.0313 0.9976 25 k 300.78 k x x x x x x xx R x R −= × = + × × × === Ω EX9.4 01 2 3 4 12 34 FF FF II I I RRRR vv v v V + + +
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
We need 12 3 4 7, 14, 3.5, 10 FF F F RR R R R R == = = Set 280 k F R Then 1 2 3 4 280 40 k 7 280 20 k 14 280 80 k 3.5 280 28 k 10 R R R R ==Ω EX9.5 We may note that 3 2 3 2 1.5 R R and 1 20 2 10 F R R so that 3 21 F R R = () ( ) 2 3 4 2 34 33 03 3 0 Then 3 2 mA 1.5 k 2 10 200 0.4 V 0.4 0.267 mA 1.5 k 0.267 2 2.267 mA 2.267 10 3 10 0.4 7.2 V I LL L L L L v ii R vi Z v i R iii Rv v −− = Ω × = = Ω =+= += =+ = × ×− = EX9.6 Refer to Fig. 9.24 11 25 k Ω Let 13 2.5 k Ω Set 24 = 0 22 Differential Gain 100 250 k 2.5 k v vR == = = Ω Ω EX9.7
Background image of page 2
[] 43 22 02 1 14 3 1 13 2 4 1 We have the general relation that / 1 1/ 10 k , 20 k , 21 k 21/10 20 20 1 10 1 10 2.0323 2.0 II RR vv v R R R R v v ⎛⎞ =+ ⎜⎟ + ⎝⎠ = =Ω=Ω=Ω + =− a. 12 00 1, 1 2.0323 2.0 4.032 V == b. 1 V 2.0323 2.0 0.0323 V = c. cm I I vvv so common-mode gain 0 0.0323 cm cm v A v d. () 10 10 20log 2.0323 1 2.0 2.016 2.016 20log 35.9 d B 0.0323 d dB cm d dB A CMRR A A = = EX9.8 42 01 2 31 2 1 v + 2 Differential gain (magnitude) 1 Minimum Gain Maximum 1 15 0 5 1 k R = Ω So 2 100 20 . 9 2 20 51 dd AA = Maximum Gain Minimum 1 1 k R 2 100 20 0 1 20 1 = Range of Differential Gain 4.92 201 EX9.9 ( ) 46 Time constant 10 0.1 10 1 m sec rR C = × = 0 1 tv t RC ≤≤ 0 At 1 m sec = 0 1 1 1 t =− + × 0 21 At 2 m sec 1 0 1 = =
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
EX9.10 01 2 3 4 10 25 80 I III vv v v v =+ From Figure 9.40, v 13 input to R 1 , v I 4 input to R 2 , v I 1 input to R A , and v I 2 input to R B .
Background image of page 4
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

This homework help was uploaded on 02/10/2008 for the course ECE 138 taught by Professor N/a during the Spring '08 term at CSU Fresno.

Page1 / 9

Ch09p - Chapter 9 Exercise Solutions EX9.1 Av = -15 = - R2...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online